Subjects · Leaving Cert Applied Maths
Leaving Cert Applied Maths: Projectile motion
How often Projectile motion comes up on the Applied Maths papers, every year it was asked, and questions to try.
HL Asked on 3 of the last 3 Higher Level papers, most recently in 2025. banker
OL Asked on 3 of the last 3 Ordinary Level papers, most recently in 2025. banker
Quick ones on Projectile motion.
- 2 s
- 4 s
- 1.43 s
- Vertical, equal to u sin α
- Zero
- Horizontal, equal to u cos α
- u sin α / g
- u cos α / g
- 2u sin α / g
Show the answers
(a) 4 s
(b) Horizontal, equal to u cos α
(c) u sin α / g
Higher Level
Asked on 3 of the last 3 Higher Level papers, most recently in 2025. banker
Every paper, year by year
| Year | Where it came up |
|---|---|
| 2025 | Q7, Q10 |
| 2024 | Q7 |
| 2023 | Q3, Q8 |
Links open the State Examinations Commission’s paper for that year.
More Projectile motion questions
Projectile motion, 3 marks
A ball hits a smooth vertical wall (perpendicular to i) with velocity 12i − 5j m/s, e = 0.5. Velocity just after?
- −6i + 2.5j m/s
- −12i − 5j m/s
- −6i − 5j m/s
Show the answer
−6i − 5j m/s
Only the component into the wall changes: it reverses and is multiplied by e, giving −6i. The j-component along the smooth wall is unchanged at −5j.
Projectile motion, 3 marks
A projectile's height is y = 19.6t − 4.9t² (g = 9.8). When is it 14.7 m high?
- t = 1 s only
- t = 1 s and t = 3 s
- t = 2 s only
Show the answer
t = 1 s and t = 3 s
4.9t² − 19.6t + 14.7 = 0 becomes t² − 4t + 3 = 0, so (t − 1)(t − 3) = 0. Once on the way up and once on the way down; t = 2 is the top.
Projectile motion, 2 marks
With no air resistance, what happens to a projectile's horizontal velocity during flight?
- It stays constant
- It decreases steadily
- It increases steadily
Show the answer
It stays constant
Gravity acts only vertically, so no force acts horizontally. The i-component u cos α stays the same from launch to landing; only the j-component changes.
Ordinary Level
Asked on 3 of the last 3 Ordinary Level papers, most recently in 2025. banker
Every paper, year by year
| Year | Where it came up |
|---|---|
| 2025 | Q6 |
| 2024 | Q4 |
| 2023 | Q5 |
Links open the State Examinations Commission’s paper for that year.
More Projectile motion questions
Projectile motion, 2 marks
With no air resistance, the vertical acceleration of a projectile is…
- 0 m s⁻²
- 9.8 m s⁻² upwards
- 9.8 m s⁻² downwards
Show the answer
9.8 m s⁻² downwards
The only force is the weight, so the acceleration is g = 9.8 m s⁻² down, on the way up and on the way down.
Projectile motion, 3 marks
A ball is thrown horizontally at 10 m s⁻¹ from a cliff. Horizontal distance after 3 s?
- 3.3 m
- 30 m
- 44.1 m
Show the answer
30 m
Horizontal velocity stays at 10 m s⁻¹, so distance = 10 × 3 = 30 m. 44.1 m is how far it has fallen vertically in 3 s.
Projectile motion, 3 marks
A projectile has u = 14i + 19.6j m s⁻¹. Time to maximum height? (g = 9.8 m s⁻²)
- 2 s
- 4 s
- 1.43 s
Show the answer
2 s
At the top the vertical velocity is 0: 0 = 19.6 − 9.8t, so t = 2 s. Only the j part matters; 1.43 wrongly uses the 14.
Other Applied Maths topics
- Calculus & variable acceleration
- Connected particles & pulleys
- Constant acceleration (suvat)
- Dijkstra's algorithm
- Displacement & velocity graphs
- First-order difference equations
- Forces & Newton's laws
- Friction & inclined planes
- Graphs & network terminology
- Horizontal circular motion
- Loans, savings & finance models
- Matrices & adjacency
- Minimum spanning trees
- Momentum & direct collisions
- Oblique collisions
- Recurrence relations & differences
- Reducing second-order DEs
- Resisted motion & drag
- Second-order difference equations
- Separable differential equations
- The modelling cycle & assumptions
- Vectors & the dot product
- Vertical circular motion
- Dimensional analysis
- Dynamic programming & Bellman
- Project scheduling & critical path
- Work, energy & conservation
- Greedy vs dynamic algorithms
- Hooke's law & elastic energy