Subjects · Leaving Cert Applied Maths
Leaving Cert Applied Maths: Vectors & the dot product
How often Vectors & the dot product comes up on the Applied Maths papers, every year it was asked, and questions to try.
HL Asked on 2 of the last 3 Higher Level papers, most recently in 2025. most years
OL Asked on 3 of the last 3 Ordinary Level papers, most recently in 2025. banker
Quick ones on Vectors & the dot product.
- 14
- 10
- 100
- Their dot product is 1
- Their magnitudes are equal
- Their dot product is 0
- 2
- 6i − 4j
- 10
Show the answers
(a) 10
(b) Their dot product is 0
(c) 2
Higher Level
Asked on 2 of the last 3 Higher Level papers, most recently in 2025. most years
Every paper, year by year
| Year | Where it came up |
|---|---|
| 2025 | Q5 |
| 2024 | Not asked |
| 2023 | Q8 |
Links open the State Examinations Commission’s paper for that year.
More Vectors & the dot product questions
Vectors & the dot product, 3 marks
Find k and t if k(i + 2j) + t(3i − j) = 7i.
- k = 2, t = 1
- k = 7, t = 0
- k = 1, t = 2
Show the answer
k = 1, t = 2
Match parts. i: k + 3t = 7. j: 2k − t = 0, so t = 2k. Then k + 6k = 7 gives k = 1 and t = 2. Check j: 2 − 2 = 0.
Vectors & the dot product, 2 marks
For any vector a, the dot product a·a equals…?
- 2|a|
- |a|²
- 0
Show the answer
|a|²
(xi + yj)·(xi + yj) = x² + y², which is the square of the magnitude. So |a| = √(a·a). The angle between a vector and itself is 0 and cos 0 = 1.
Vectors & the dot product, 3 marks
|a| = 4, |b| = 5 and a·b = 10. Angle between a and b?
- 60°
- 30°
- 90°
Show the answer
60°
cos θ = a·b ÷ (|a||b|) = 10 ÷ 20 = 0.5, so θ = 60°. A dot product of 0 would mean 90°.
Ordinary Level
Asked on 3 of the last 3 Ordinary Level papers, most recently in 2025. banker
Every paper, year by year
| Year | Where it came up |
|---|---|
| 2025 | Q8 |
| 2024 | Q2 |
| 2023 | Q3 |
Links open the State Examinations Commission’s paper for that year.
More Vectors & the dot product questions
Vectors & the dot product, 3 marks
Find (2i + 3j)·(4i − j).
- 11
- 8i − 3j
- 5
Show the answer
5
Multiply matching parts and add: 2 × 4 + 3 × (−1) = 8 − 3 = 5. A dot product is a number (scalar), not a vector.
Vectors & the dot product, 3 marks
Find k if (ki + 2j)·(3i − 6j) = 0.
- k = 2
- k = 4
- k = −4
Show the answer
k = 4
Dot product: 3k + 2 × (−6) = 3k − 12 = 0, so k = 4. The vectors are then perpendicular.
Vectors & the dot product, 2 marks
Two non-zero vectors are perpendicular when their dot product is…
- 0
- 1
- −1
Show the answer
0
a·b equals the product of the magnitudes times cos θ. At 90°, cos θ = 0, so the dot product is 0.
Other Applied Maths topics
- Calculus & variable acceleration
- Connected particles & pulleys
- Constant acceleration (suvat)
- Dijkstra's algorithm
- Displacement & velocity graphs
- First-order difference equations
- Forces & Newton's laws
- Friction & inclined planes
- Graphs & network terminology
- Horizontal circular motion
- Loans, savings & finance models
- Matrices & adjacency
- Minimum spanning trees
- Momentum & direct collisions
- Oblique collisions
- Projectile motion
- Recurrence relations & differences
- Reducing second-order DEs
- Resisted motion & drag
- Second-order difference equations
- Separable differential equations
- The modelling cycle & assumptions
- Vertical circular motion
- Dimensional analysis
- Dynamic programming & Bellman
- Project scheduling & critical path
- Work, energy & conservation
- Greedy vs dynamic algorithms
- Hooke's law & elastic energy